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u^2+11u-126=0
a = 1; b = 11; c = -126;
Δ = b2-4ac
Δ = 112-4·1·(-126)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-25}{2*1}=\frac{-36}{2} =-18 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+25}{2*1}=\frac{14}{2} =7 $
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